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Robot on 7 Oct 2014
Commented: Robot on 9 Oct 2014
Accepted Answer: Mohammad Abouali
I would like to subset a table into columns before a certain variable and columns after that variable. Is there a way to locate a column number within a table? Is there a more clever way to do this?
load patients
BloodPressure = [Systolic Diastolic];
T = table(Gender,Age,Smoker,BloodPressure,'RowNames',LastName);
A = *findColNumber*(T, 'Age'); % Some function that will locate the column number of 'Age'.
T1 = T(:, 1:A);
T2 = T(:, A+1:end);
'patients' is a standard example data set included in R2014a. Entering the command 'load patients' should load the relevant data.
Thanks!
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Accepted Answer
Mohammad Abouali on 8 Oct 2014
Table variable have property fields
you can use that to find the column number like this
find(strcmpi(T.Properties.VariableNames,'Age'))
ans =
2
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Image Analyst on 8 Oct 2014
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Cool - I didn't know about that. You taught me something. Of course he still won't be able to do what he wants to do (I tried).
Mohammad Abouali on 8 Oct 2014
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https://www.mathworks.com/matlabcentral/answers/157742-find-column-number-in-table#comment_241524
load patients
BloodPressure = [Systolic Diastolic];
T = table(Gender,Age,Smoker,BloodPressure,'RowNames',LastName);
A = find(strcmpi(T.Properties.VariableNames,'Age'));
T1 = T(:, 1:A);
T2 = T(:, A+1:end);
Strange. This works for me.
And I have learned also a lot from your posts and your matlab examples.
Image Analyst on 8 Oct 2014
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Edited: Image Analyst on 8 Oct 2014
Yeah, your T is slightly different than mine. No time now, but tomorrow I'll have to investigate why your code and mine behave differently and have slightly different T's. You'd think they should be the same even though they were gotten in different ways.
Actually I just figured it out. With my code, load() returns T as a structure not a table. So that makes sense.
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More Answers (1)
Image Analyst on 7 Oct 2014
You don't need the column number. Just do
ages = T.Age;
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Robot on 7 Oct 2014
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Thanks for the response, however T.Age will return the values within column 'Age'. I am looking for the column number for 'Age' (IE: A = 2).
Image Analyst on 8 Oct 2014
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Edited: Image Analyst on 8 Oct 2014
You can get the age column like this:
T = load('patients')
ageColumn = find(ismember(fieldnames(T), 'Age'))
Image Analyst on 8 Oct 2014
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Actually T is a structure, so I recommend Mohammad's way.
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